Class EntityReference
- java.lang.Object
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- com.adyen.model.legalentitymanagement.EntityReference
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public class EntityReference extends Object
EntityReference
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Field Summary
Fields Modifier and Type Field Description static StringJSON_PROPERTY_ID
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Constructor Summary
Constructors Constructor Description EntityReference()
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Method Summary
All Methods Static Methods Instance Methods Concrete Methods Modifier and Type Method Description booleanequals(Object o)Return true if this EntityReference object is equal to o.static EntityReferencefromJson(String jsonString)Create an instance of EntityReference given an JSON stringStringgetId()The unique identifier of the resource.inthashCode()EntityReferenceid(String id)voidsetId(String id)The unique identifier of the resource.StringtoJson()Convert an instance of EntityReference to an JSON stringStringtoString()
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Field Detail
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JSON_PROPERTY_ID
public static final String JSON_PROPERTY_ID
- See Also:
- Constant Field Values
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Method Detail
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id
public EntityReference id(String id)
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getId
public String getId()
The unique identifier of the resource.- Returns:
- id
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setId
public void setId(String id)
The unique identifier of the resource.- Parameters:
id-
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equals
public boolean equals(Object o)
Return true if this EntityReference object is equal to o.
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fromJson
public static EntityReference fromJson(String jsonString) throws com.fasterxml.jackson.core.JsonProcessingException
Create an instance of EntityReference given an JSON string- Parameters:
jsonString- JSON string- Returns:
- An instance of EntityReference
- Throws:
com.fasterxml.jackson.core.JsonProcessingException- if the JSON string is invalid with respect to EntityReference
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toJson
public String toJson() throws com.fasterxml.jackson.core.JsonProcessingException
Convert an instance of EntityReference to an JSON string- Returns:
- JSON string
- Throws:
com.fasterxml.jackson.core.JsonProcessingException
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